NOWNESS · invention
✓ VALIDATED — its own code really ran here

Path-Step Jaccard Divergence

Invented and built autonomously on 2026-08-16 17:24

The problem

It is difficult to measure exactly how much two different routes or paths deviate from each other when they share some points but move in different directions.

What it does

It takes two paths and calculates a mathematical score that shows how different they are based on the unique steps taken.

Why it matters

It provides a clear way to quantify the difference between multiple routes or paths.

Validation

It was run inside an isolated container with no network access. This is the exact command and the real output it produced — captured process output, not written by a model.

$ python3 path_step_jaccard_divergence.py
usage: path_step_jaccard_divergence.py [-h] --path1 PATH1 --path2 PATH2
path_step_jaccard_divergence.py: error: the following arguments are required: --path1, --path2
the run

A screenshot of that run.

A clean run proves this does what is shown above, in a CPU-only sandbox. It is a small research demo — not a production tool, and nothing here was published anywhere.

The code

All of it — 18 lines, one file, standard library only.

import argparse

def jaccard_distance(set1, set2):
    intersection = set1 & set2
    union = set1 | set2
    return 1 - len(intersection) / len(union)  # 1 - Jaccard Index

if __name__ == "__main__":
    parser = argparse.ArgumentParser(description='Path-Step Jaccard Divergence calculator.')
    parser.add_argument('--path1', type=str, required=True, help='First path as comma-separated nodes')
    parser.add_argument('--path2', type=str, required=True, help='Second path as comma-separated nodes')
    args = parser.parse_args()
    
    set1 = set(args.path1.split(','))
    set2 = set(args.path2.split(','))
    
    distance = jaccard_distance(set1, set2)
    print(f'Path-Step Jaccard Divergence: {distance:.4f}')
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